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Derivatives of sec(x) and csc(x) | Derivative rules | AP Calculus AB | Khan Academy - JJtheTutor
Sal finds the derivatives of sec(x) and csc(x) by writing them as 1/sin(x) or 1/cos(x) and using quotient rule. Practice this lesson yourself on KhanAcademy.org right now: https://www.khanacademy.org/math/ap-calculus-ab/ab-derivative-rules/ab-diff-trig-func/e/differentiate-basic-trigonometric-functions?utm_source=YT&utm_medium=Desc&utm_campaign=APCalculusAB Watch the next lesson: https://www.khanacademy.org/math/ap-calculus-ab/ab-derivative-rules/ab-diff-trig-func/v/trig-functions-differentiation-sec?utm_source=YT&utm_medium=Desc&utm_campaign=APCalculusAB Missed the previous lesson? https://www.khanacademy.org/math/ap-calculus-ab/ab-derivative-rules/ab-diff-trig-func/v/derivatives-of-tanx-and-cotx?utm_source=YT&utm_medium=Desc&utm_campaign=APCalculusAB ?utm_source=YT&utm_medium=Desc&utm_campaign=APCalculusAB AP Calculus AB on Khan Academy: Bill Scott uses Khan Academy to teach AP Calculus at…