The Man Who Knew Infinity (2015)

The Man Who Knew Infinity (2015)

Emotional moment for a fan during Infinity War pane Q&A at Rhode Island Comic Con. Sebastian Stan giving love in return.

Baekhyun // 160917 Infinity Challenge #4

How Avengers: Infinity War ends.

Tony gets blackout drunk one night, somehow kills Thanos by himself and creates a intricate deathtrap for all the other Avengers to take his baggage out on them because he’s insecure about losing Peter.

Listen

External image

Thanks for Everything ya guys~ & for a Year we reached a total of **3,130+** Followers, like Damn, really didn’t expect that coming~ but Thanks, thank you for the LOVE, the SUPPORT, the CHEERY stuff everytime i’m down to the grave (even thou i was always like that) but thank you all~~ I couldn’t be improving in my art (does it even improve?), i actually want to stop doing art before but the MaMa TrAsh insisted me to keep on & maybe post some of it to get more love & support, turns out i still wanna stop, just kidding~~

But for sure, I’ll keep on doing ‘em for you~ ♥♥

Thanks for everything~

~~Sorry, i dun talk much, cuz it gets weird & weird & awkward~ Just Thanks to the raise of Infinity~~~

i’ve got all this ringing in my ears and none on my fingers // fall out boy

**Taylor:**I've figured out why you're such a jerk. You have updog.**T2:**What's "updog?"**Taylor [yelling out the door]:**Arika, get in here! I told you I could do it!

okay but if ‘fooled around and fell in love’ isn’t played at the pepperony wedding it isn’t pep & tony’s wedding

kagome “i’m tired” higurashi

**hollandville** on instagram recorded the part where tom basically confirms that he’s filming for infinity war !!!!

**Interviewer: **So when are we going to get the Vision and Scarlet Witch movie?

**Anthony Russo: **It’s called Avengers: Infinity War.

—
Full Q&A interview with The Russo Brothers, ColliderVideos (x)

Admiralpotato, “Q*bert Club”, Utah Museum Of Contemporary Art (UMOCA).

Hum Hallelujah // Fall Out Boy

Hum Hallelujah // Infinity On High

**T2:**You’re stupid.**Taylor:**That’s it?**T2:**Give it time. It’ll eat at you.- [later]
**Taylor:**Am I stupid?**Lifeline:**Yeah, a little bit.**Taylor [mentally]:**Damn them!

“same-sized” infinities

The idea of “two sets are the same size iff there is a bijection between them” leads to the interesting property that you can extend the idea of size to infinite sets.

Here are illustrations of how two infinite size sets can have the same size, some of which might seem surprising if you are only used to finite sizes.

Some sets I will use as examples are integers Z={…,-2,-1,0,1,2,…}, positive integers Z^{+}={1,2,3…}, non-negative integers Z^{*}={0,1,2,3…}, the non-negative even integers 2Z^{*}={0,2,4,6,…}, the positive rational numbers Q={p/q : p,q are positive integers and q is not 0}, and positive real numbers R^{+}, which include the irrationals.

**Z ^{+} and Z* are the same size**

The function is f:Z*->Z^{+}, f(x)=x+1

**Z ^{*} and 2Z* are the same size**

The function is f:Z*->2Z^{*}, f(x)=2x

**Z ^{*} and Z are the same size**

The function is one where we split Z* into evens and odds, and then take the evens to the negatives and the odds to the positives

**Q on the interval [1,infinity) and Q on the interval (0,1] are the same size**

The function is f:Q[1,infinity)->Q(0,1], f(x)=1/x. (We can also use a similar function to show any interval of real numbers has the same size as the entire real number line)

**Z ^{*} and Q* are the same size**

This one is a bit trickier. We will show that Z* is the same size as the cartesian product Z*×Z*, and notice that Q* is a subset of Z*×Z*, so cannot be larger than it, but Q* contains Z*, so it cannot be smaller.

First, we split the cartesian product into lines based on the sum of the two numbers in each pair

Let t(n) be the n^{th} triangular number, or the sum of all non-negative integers below and including it. Notice that t(p+q) is the number of pairs with sum below p+q, because each row where the sum is m has m-1 elements.

We construct a function f:Z*×Z*->Z*, f(p,q)=t(p+q)+p

**R and R×R have the same size**

First, we restrict R to the interval [0,1), which has the same size as R. Then, we realize that we can represent each real number by its decimal expansion, which has a Z^{+} sized expansion. We can split every expansion into even and odd number places, and make a new number in R×R restricted to [0,1)×[0,1) using the two expansions to make its two numbers.