can't believing


Happy 5 years of Red!

My experiences in love have taught me difficult lessons, especially my experiences with crazy love. The red relationships. The ones that went from zero to a hundred miles per hour and then hit a wall and exploded. And it was awful. And ridiculous. And desperate. And thrilling. And when the dust settled, it was something I’d never take back. Because there is something to be said for being young and needing someone so badly, you jump in head first without looking. And there’s something to be learned from waiting all day for a train that’s never coming. And there’s something to be proud of about moving on and realizing that real love shines golden like starlight, and doesn’t fade or spontaneously combust. Maybe I’ll write a whole album about that kind of love if I ever find it. But this album is about the other kids of love that I’ve recently fallen in and out of. Love that was treacherous, sad, beautiful, and tragic. But most of all, this record is about love that was red.❞ // October 22, 2012

anonymous asked:

what do u think is the slope of namjoon's ass?

1. locate photo (cr)

2. because the selected shape is currently NOT a function (doesn’t pass vertical line test), we must flip the photo on its side so we can restrict the domain and then take the derivative of the function.

3. this section matches up pretty well with a log graph. i graphed the function “log(-2x)” on to model the function (seen below)

4. then i took the derivative of my function [g(x)=d(f(x))/dx AKA f’(x)].

this can also be done using chain rule, if you don’t have a graphing calculator. your original function is f(x) = log(-2x) and then it will become f’(x) = [1/(-2xln10)]*-2. the only problem with that is f’(x) will have a positive section for the deriv function, and those points cannot be used because log graphs have restricted domain

5. technically, any point on the purple graph [f’(x) AKA g(x)] will give u the slope of a corresponding point for the original graph [f(x)]. since log graphs (like all function U take the derivatives of) are curved, MANY MANY MANY (an infinite number) of tangent lines can be drawn, which means there are also an INFINITE number of slopes for the function.

however, you can pick and choose any point on the f(x) = log(-2x) graph that are within the restricted domain to match the shape of namjoon’s ass to look for the slope @ a point.

Junkrat Sings The Philosophers Song
Junkrat Sings The Philosophers Song

@creativecalico requested I do an Aussie pub song. Unfortunately, while I know plenty of Irish pub songs, I don’t know any Aussie ones. Lucky for us, Junkrat just happens to be an honorary member of the Philosophy Department of the University of Junkertown, so he was able to fill in the gaps for us.