2

scissor paper

오버사이즈 T 2color

ekaura

*Follow*

2

scissor paper

오버사이즈 T 2color

ekaura

8

Justin Bieber + Colors:Black & White

demisfighter

8

Consider tiling the plane using only square tiles like this:

The 4-fold rotational symmetry of the square allows a tile to be placed in the 4 different orientations shown here:

Despite these constraints there are still a lot of different ways to tile the plane. Shown above are a few examples constructed with an algorithm using modular arithmetic. This essentially makes the tiles along different rows follow the same sequence but shifted over by some amount.

Each of the tilings shown are actually periodic and can tile the entire plane.

(e.g. 1, 2, 3, 4)

Tilings of this variety are called Truchet tilings.

Mathematica code:

T[r_, x_, y_] :=

Translate[

Rotate[

{EdgeForm[Thickness[0]], Polygon[{{1, 0}, {0, 0}, {0, 1}}]},

r, {.5, .5}],

{x, y}]

Manipulate[

Graphics[

Table[

T[Mod[a*x + b*y, m] Pi/2, x, y],

{x, 1, X, 1}, {y, 1, Y, 1}],

PlotRange -> {{1, X}, {1, Y - .1}}, ImageSize -> 500],

{{X, 29}, 1, 100, 1}, {{Y, 29}, 1, 100, 1},

{{m, 14}, 1, 100, 1},

{{a, 5}, 1, 100, 1},

{{b, 5}, 1, 100, 1}]

intothecontinuum

sneakerwars

6

kiritori-graphics

8

Justin Bieber + Colors:Purple & Red

demisfighter

A 2-coloring of what results from playing connect-the-dots with the complex numbers z^{n}, for 0 < n < 100, as z varies from e^{i2.595} to e^{i2.599}.

Mathematica code:

ListAnimate[

Table[

Graphics[

GraphicsComplex[

Table[

{-1^n*Sin[n*a], 1^n*Cos[n*a]}, {n, 0, 100}],

Polygon[Table[i, {i, 1, 100, 1}]]],

PlotRange -> .65, ImageSize -> 500],

{a, 2.59523, 2.59994, .00015}]]

intothecontinuum

"2colors",Poznań,2014

asphaltwildstories

sneakerwars

5to sorteo 🙆 vengan vengan!!! www.facebook.com/jolsetienda esta vez…. #pintalabios 💋 de #lioele 2colores

jolsetienda

Planar 2-colorability

Take some region of the plane, and any number of distinct lines that pass anywhere *through* this region. Consider these random lines for instance:

Notice how the lines and their crossings create polygonal shapes in the region.

Using just two colors, say black and white, is it possible to color the entire region such that any two polygons that are next to each other sharing a common edge are different colors?

This is possible in the above example as this 2-coloring indicates:

There is also another possible 2-coloring that satisfies these requirements, but its really just the same as the 2-coloring above with the colors switched.

You can convince yourself that these are the only two permissible 2-colorings meeting the criterion with this particular configuration of lines.

One may wonder if its always possible to achieve such a 2-coloring, or precisely under what circumstances it is or is not possible.

It does seem to be the case that if each line passes completely through the region, then a 2-coloring will always be possible.

The following examples show this for two particular cases, where not only are there a different number of randomly chosen lines in each case, but each line is even allowed to move. Regardless, at each instance, the 2-coloring is always preserved!

Still, these examples do not prove the claim in general since there remains an infinite number of cases left unconsidered. How would one prove this?

Well, when would such a 2-coloring *not* be possible?

At any intersection of lines in the region, the crossings create corners for the polygons that are formed. If there happens to be an intersection with an *odd number* of corners, then for any assignment of 2 colors to the parts around this intersection, there would have to exist two adjacent parts that have the same color. Otherwise, for an *even* number of corners around an intersection, it is always possible to assign a 2-coloring so that adjacent parts have different colors.

Therefore, as long as all the intersections formed *within* the region have an *even* number of corners, there will exist a 2-coloring. This criterion will be met if we assume that the lines always pass completely through the region as in previous considerations

These conditions are special and do limit the possible configurations that are 2-colorable.

What if configurations were allowed to have intersections with an odd number of corners?

What if lines didn’t have to pass completely through the region and were allowed to end somewhere inside of it?

What if we didn’t have to use straight lines to partition the region?

If it is not possible to color the region in the above sense with 2 colors, how many would it take?

Does there exist some maximum finite number of colors that can be used to color any possible partition of a region?

The 4-color theorem, first stated in 1852, which concerns the problem under consideration, states that only 4 colors are needed to color any configuration so that adjacent regions are not colored the same.

The truth of this theorem went without correct proof until 1976 when it was proved by Kenneth Appel and Wolfgang Haken using a computer! This computer-assisted proof may be considered controversial and has interesting implications.

It is worth mentioning that the related problem of deciding whether a given configuration is 2-colorable is easy to solve since there are efficient computer algorithms that can check. However, the problem of deciding if 3 colors are needed is hard to do in general since there are currently no known computers algorithms that can efficiently solve this problem.

If you can find a fast algorithm, or if it you can prove that no efficient algorithm can exist for deciding the 3-coloring problem, then you could win $1,000,000 solving a big open problem in computer science.

intothecontinuum

jonaimilinjapan

Thanks to a little help from both of my printshop partners, these bad boys got finished on time. Thank you Stevie at 3E/Second City Prints and Dave at @teesyou for taking the time from your day to make that happen for me. #scottstapp #creed #tourposter #concertposter #concert #poster #screenprinting #2color #halftone #handmade #print #design #mojoesofjoliet #joliet (at Mojoes)

jaimeradar

$87 More Back in stock! #romper #2colors #scarletbrand (at scarlet headquarters)

scarletclothing

catsgram

17位：AA34【先行予約受付！予約限定10％OFF☆8月20日〜2,700円→2,430円】Rora ライビー カーディガン(2color)】お袖のタックと3つずつあしらったグログランのリボンのガーリー度に注目★【楽ギフ_包装】 http://ift.tt/1mYnJK7 ＜ー購入はコチラから！＊＊＊＊＊鈴木心愛@躁うつ病患者 鈴木心愛です。 http://p.tl/AI7n http://p.tl/E5sZ http://p.tl/vw4w http://p.tl/zQob http://p.tl/FgKW http://p.tl/xVQ4 躁鬱病・躁うつ病・双極性障害です。 2012年2月1日から正式復職。 リスパダールとラミクタールを服用しています。 気分がUpDownしますが、宜しくお願い致します。 栃木県宇都宮市

cocoa-suzuki-desu

bearjong-quxxnrin

#제이앤룩 #jnlook

2color(sky/gray) 3size(s,m,l)

₩ 29,000 / ₩ couple 55,000(-3,000)

여자- 키160/55사이즈 gray(s) 착용

남자- 키187/100,105사이즈 gray(l) 착용

구입문의 댓글 / kakao - jinju4628

#커플룩 #커플남방 #스트라이프남방 #롤업

#차이나카라 #트윈룩 #시밀러룩 by jnlook http://instagram.com/p/sGbcsklj9V/

thelandofboonationlove

18位：【先行予約受付！予約限定15％OFF☆8月20日〜2,900円→2,465円】コラボサイズ140cmまで展開【Roraボボ スカッツ (2color)】チュールレースのスソがフリフリとゆれてかわいさいっぱい♪みんな大好きスカッツ！ http://ift.tt/1mYnIGg ＜ー購入はコチラから！＊＊＊＊＊鈴木心愛@躁うつ病患者 鈴木心愛です。 http://p.tl/AI7n http://p.tl/E5sZ http://p.tl/vw4w http://p.tl/zQob http://p.tl/FgKW http://p.tl/xVQ4 躁鬱病・躁うつ病・双極性障害です。 2012年2月1日から正式復職。 リスパダールとラミクタールを服用しています。 気分がUpDownしますが、宜しくお願い致します。 栃木県宇都宮市

cocoa-suzuki-desu

So any votes on:

1outline

2color

3both

4leave as is

Love to hear your guys response.

yuihatsune